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Geom. Help plz


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this is probably really wrong... but yea here goes lmao ..i havent taken math for about 5 months ....

first off find the area of the first two triangles...

a of triangle = b x h / 2 find the height of the triangle.. if its equaliteral its base is gunna be 1 side..so now u have to find the height ...if its equaliteral you can use pythagreous theorm ...split draw a line down the middle to form a right angle triangle, u know the base of the right angle triangle is = half the side lenght, and the hypothneus is = side length ..and u have to solve for the height

10^2 = 5^2 + x^2

100=25+x^2

75=x^2

sqrroot75 = 8.66

this will give you the height of the triangle

to find the area plug into the equation

so it will be 8.66 x 10 / 2 = 43.3 = aTriangleI

now to do triangle II

24^2=12^2+x^2

576=144+x^2

432=x^2

sqrroot 432 = 20.78

plug into equation.. 20.78 x 12 / 2 = 124.68 = aTriangleII

now u have the areas of the two triangles u can figure out the area if the third triangle by adding the two

124.68 + 43.3 = 167.98 = aTriangleIII

now u know that you can plug into the equation A = b x h / 2

so 167.98 = b x h / 2

multiply by to to get rid of the 2 on that side..

now ur left with 335.96 = b x h

----------------------------------Im pretty sure up to here is right... goodluck ...lol

you have to be left with only 1 variable so you know h = sqrroot(b^2-1/2b^2)

so now ur left with 335.96 = b(sqrroot(b^2-1/2b^2)

the square root will cancel out the squares so you're left with

335.96=b(b-1/2b) you expand

335.96=b^2-1/2b^2 you multiply everything by 2 to get rid of the 1/2

so its going to be 671.92=2b^2-b^2

671.92=b^2

sqrroot(671.92)=b

and b=25.92 = 26feet

b=base = 1 side in a equaliteral triangle so 26feet = ur anwser

its probably wrong.. lemme check...

this is wrong.. if u do the formula you will get 146.25 as the area of a triangle with 26feet on each side

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i thought u were getting a 3.89 gpa and that u weren't trying? :)

anyways. find the height of each triangle by using the pythagorean theorem switching around the formukla to c2-b2=a2 don't forget since ur trying to find the height that means ur cutting the base in half so b would be 12 for triangle 2 and 5 for triangle 1 and the forumla would be:

(24)2-(12)2=a2

do that with the other triangle

after u find the heights find the area and then add them.

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