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RKDMAN -
post Nov 6 2007, 05:02 PM
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okay im doing basic 8th grade algebra heres an example of what some of questions are like 0.4(7x-4)=5(5x-7) stuff like that im just wondering if their are ne tips to help me remember and get this stuff good thanks in advance.


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Jesus -
post Nov 6 2007, 11:16 PM
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distribute and then get all the x's to 1 side.
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Pete -
post Nov 7 2007, 04:27 PM
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You just gotta egual the equation to Zero then you factorize and then you isolate your zero so it could goes like that

4(7x-4)=5(5x-7)

28x-16 =25x-35

28x-25x-16-35=0

3x-51=0

3(x - 17)=0

x=17 cause (x-17)=0


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Jesus -
post Nov 7 2007, 07:33 PM
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QUOTE(Pete @ Nov 7 2007, 05:27 PM) *
You just gotta egual the equation to Zero then you factorize and then you isolate your zero so it could goes like that

4(7x-4)=5(5x-7)

28x-16 =25x-35

28x-25x-16-35=0

3x-51=0

3(x - 17)=0

x=17 cause (x-17)=0


dont listen to this guy, plug 17 into the original problem and you get 460=390...

4(7x-4)=5(5x-7)

28x-16=25x-35

3x-16=-35

3x=-19

x=-6 1/3
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Pete -
post Nov 7 2007, 07:43 PM
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QUOTE(Jesus @ Nov 7 2007, 08:33 PM) *
QUOTE(Pete @ Nov 7 2007, 05:27 PM) *
You just gotta egual the equation to Zero then you factorize and then you isolate your zero so it could goes like that

4(7x-4)=5(5x-7)

28x-16 =25x-35

28x-25x-16-35=0

3x-51=0

3(x - 17)=0

x=17 cause (x-17)=0


dont listen to this guy, plug 17 into the original problem and you get 460=390...

4(7x-4)=5(5x-7)

28x-16=25x-35

3x-16=-35

3x=-19

x=-6 1/3


my thing just doesnt work cause i made it with 4 instead of 0.4

But my way is the good algebric way to find it

the way of jesus wont get you the whole answer if youre x has 2 values or more ( x^2 or more )


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Jesus -
post Nov 8 2007, 02:11 AM
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QUOTE(Pete @ Nov 7 2007, 08:43 PM) *
QUOTE(Jesus @ Nov 7 2007, 08:33 PM) *
QUOTE(Pete @ Nov 7 2007, 05:27 PM) *
You just gotta egual the equation to Zero then you factorize and then you isolate your zero so it could goes like that

4(7x-4)=5(5x-7)

28x-16 =25x-35

28x-25x-16-35=0

3x-51=0

3(x - 17)=0

x=17 cause (x-17)=0


dont listen to this guy, plug 17 into the original problem and you get 460=390...

4(7x-4)=5(5x-7)

28x-16=25x-35

3x-16=-35

3x=-19

x=-6 1/3


my thing just doesnt work cause i made it with 4 instead of 0.4

But my way is the good algebric way to find it

the way of jesus wont get you the whole answer if youre x has 2 values or more ( x^2 or more )


you use a different formula if you have x^2 or more...
please don't try to help people with math if you don't know the first thing about it.
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foxshox -
post Nov 8 2007, 01:05 PM
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QUOTE(RKDMAN @ Nov 6 2007, 05:02 PM) *
okay im doing basic 8th grade algebra heres an example of what some of questions are like 0.4(7x-4)=5(5x-7) stuff like that im just wondering if their are ne tips to help me remember and get this stuff good thanks in advance.

Alright heres what you do:
First since you see the decimal to the *tenths* place, you multiply the whole thing by 10 like:
10*.4(7x-4)=10*5(5x-7)
4(7x-4)=50(5x-7)
Then just work through it like so
28x-16=250x-350
350-16=250x-28x
334=222x
334/222=x

You can still distribute the .4, but if your new to this, keeping them round numbers makes it easier to look at.

Whatever place the decimal is like "tenth" or 'hundredth" multiply it by 10 or 100 respectively. So if it was .05(3x-2)=4(3x-4).. you see its to the 100th place, so you multiply it by 100 and get 5(3x-2)=400(3x-4).

Just so long as you multiply both sides by the same number, it will have no effect on the answer itself.

This post has been edited by foxshox: Nov 8 2007, 01:06 PM
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WhyteBoi -
post Nov 9 2007, 09:10 PM
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unless its zero derisive.gif


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foxshox -
post Nov 10 2007, 03:35 AM
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Uhh actually, if you multiply by zero, it will give you 0=0, which is true. It won't give you a definitive answer, but it won't be wrong.
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RKDMAN -
post Nov 10 2007, 07:27 PM
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QUOTE(foxshox @ Nov 8 2007, 02:05 PM) *
QUOTE(RKDMAN @ Nov 6 2007, 05:02 PM) *
okay im doing basic 8th grade algebra heres an example of what some of questions are like 0.4(7x-4)=5(5x-7) stuff like that im just wondering if their are ne tips to help me remember and get this stuff good thanks in advance.

Alright heres what you do:
First since you see the decimal to the *tenths* place, you multiply the whole thing by 10 like:
10*.4(7x-4)=10*5(5x-7)
4(7x-4)=50(5x-7)
Then just work through it like so
28x-16=250x-350
350-16=250x-28x
334=222x
334/222=x

You can still distribute the .4, but if your new to this, keeping them round numbers makes it easier to look at.

Whatever place the decimal is like "tenth" or 'hundredth" multiply it by 10 or 100 respectively. So if it was .05(3x-2)=4(3x-4).. you see its to the 100th place, so you multiply it by 100 and get 5(3x-2)=400(3x-4).

Just so long as you multiply both sides by the same number, it will have no effect on the answer itself.



ok guys this is the answer i was looking for thanks alot man. this actually helps i got a exam tuesday smile.gif i think ill get aq good grade


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